The Stacks project

Lemma 37.3.1. Let $(f, f') : (X \subset X') \to (S \subset S')$ be a morphism of thickenings. Then

  1. $f$ is an affine morphism if and only if $f'$ is an affine morphism,

  2. $f$ is a surjective morphism if and only if $f'$ is a surjective morphism,

  3. $f$ is quasi-compact if and only if $f'$ quasi-compact,

  4. $f$ is universally closed if and only if $f'$ is universally closed,

  5. $f$ is integral if and only if $f'$ is integral,

  6. $f$ is (quasi-)separated if and only if $f'$ is (quasi-)separated,

  7. $f$ is universally injective if and only if $f'$ is universally injective,

  8. $f$ is universally open if and only if $f'$ is universally open,

  9. $f$ is quasi-affine if and only if $f'$ is quasi-affine, and

  10. add more here.

Proof. Observe that $S \to S'$ and $X \to X'$ are universal homeomorphisms (see for example Morphisms, Lemma 29.45.6). This immediately implies parts (2), (3), (4), (7), and (8). Part (1) follows from Lemma 37.2.3 which tells us that there is a 1-to-1 correspondence between affine opens of $S$ and $S'$ and between affine opens of $X$ and $X'$. Part (9) follows from Limits, Lemma 32.11.5 and the remark just made about affine opens of $S$ and $S'$. Part (5) follows from (1) and (4) by Morphisms, Lemma 29.44.7. Finally, note that

\[ S \times _ X S = S \times _{X'} S \to S \times _{X'} S' \to S' \times _{X'} S' \]

is a thickening (the two arrows are thickenings by Lemma 37.2.4). Hence applying (3) and (4) to the morphism $(S \subset S') \to (S \times _ X S \to S' \times _{X'} S')$ we obtain (6). $\square$


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