## Tag `0AV7`

Chapter 15: More on Algebra > Section 15.21: Reflexive modules

Lemma 15.21.10. Let $R$ be a Noetherian ring. Let $\varphi : M \to N$ be a map of $R$-modules. Assume that for every prime $\mathfrak p$ of $R$ at least one of the following happens

- $M_\mathfrak p \to N_\mathfrak p$ is injective, or
- $\mathfrak p \not \in \text{Ass}(M)$.
Then $\varphi$ is injective.

Proof.Let $\mathfrak p$ be an associated prime of $\mathop{\rm Ker}(\varphi)$. Then there exists an element $x \in M_\mathfrak p$ which is in the kernel of $M_\mathfrak p \to N_\mathfrak p$ and is annihilated by $\mathfrak pR_\mathfrak p$ (Algebra, Lemma 10.62.15). This is impossible in both cases. Hence $\text{Ass}(\mathop{\rm Ker}(\varphi)) = \emptyset$ and we conclude $\mathop{\rm Ker}(\varphi) = 0$ by Algebra, Lemma 10.62.7. $\square$

The code snippet corresponding to this tag is a part of the file `more-algebra.tex` and is located in lines 4419–4429 (see updates for more information).

```
\begin{lemma}
\label{lemma-check-injective-on-ass}
Let $R$ be a Noetherian ring. Let $\varphi : M \to N$ be a map of
$R$-modules. Assume that for every prime $\mathfrak p$
of $R$ at least one of the following happens
\begin{enumerate}
\item $M_\mathfrak p \to N_\mathfrak p$ is injective, or
\item $\mathfrak p \not \in \text{Ass}(M)$.
\end{enumerate}
Then $\varphi$ is injective.
\end{lemma}
\begin{proof}
Let $\mathfrak p$ be an associated prime of $\Ker(\varphi)$.
Then there exists an element $x \in M_\mathfrak p$ which is
in the kernel of $M_\mathfrak p \to N_\mathfrak p$ and is
annihilated by $\mathfrak pR_\mathfrak p$
(Algebra, Lemma \ref{algebra-lemma-associated-primes-localize}).
This is impossible in both cases. Hence
$\text{Ass}(\Ker(\varphi)) = \emptyset$ and we conclude $\Ker(\varphi) = 0$ by
Algebra, Lemma \ref{algebra-lemma-ass-zero}.
\end{proof}
```

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