# The Stacks Project

## Tag 00HI

Lemma 10.38.7. Suppose that $M$ is (faithfully) flat over $R$, and that $R \to R'$ is a ring map. Then $M \otimes_R R'$ is (faithfully) flat over $R'$.

Proof. For any $R'$-module $N$ we have a canonical isomorphism $N \otimes_{R'} (R'\otimes_R M) = N \otimes_R M$. Hence the desired exactness properties of the functor $-\otimes_{R'}(R'\otimes_R M)$ follow from the corresponding exactness properties of the functor $-\otimes_R M$. $\square$

The code snippet corresponding to this tag is a part of the file algebra.tex and is located in lines 8529–8533 (see updates for more information).

\begin{lemma}
\label{lemma-flat-base-change}
Suppose that $M$ is (faithfully) flat over $R$, and that $R \to R'$
is a ring map. Then $M \otimes_R R'$ is (faithfully) flat over $R'$.
\end{lemma}

\begin{proof}
For any $R'$-module $N$ we have a canonical
isomorphism $N \otimes_{R'} (R'\otimes_R M) = N \otimes_R M$. Hence the desired exactness properties of the functor
$-\otimes_{R'}(R'\otimes_R M)$ follow from
the corresponding exactness properties of the functor $-\otimes_R M$.
\end{proof}

There are no comments yet for this tag.

There is also 1 comment on Section 10.38: Commutative Algebra.

## Add a comment on tag 00HI

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the lower-right corner).