# The Stacks Project

## Tag 032Q

Lemma 10.155.17. Let $R$ be a ring. If $R$ is Noetherian, a domain, and N-2, then so is $R[[x]]$.

Proof. Observe that $R[[x]]$ is Noetherian by Lemma 10.30.2. Let $R' \supset R$ be the integral closure of $R$ in its fraction field. Because $R$ is N-2 this is finite over $R$. Hence $R'[[x]]$ is finite over $R[[x]]$. By Lemma 10.36.9 we see that $R'[[x]]$ is a normal domain. Apply Lemma 10.155.16 to the element $x \in R'[[x]]$ to see that $R'[[x]]$ is N-2. Then Lemma 10.155.7 shows that $R[[x]]$ is N-2. $\square$

The code snippet corresponding to this tag is a part of the file algebra.tex and is located in lines 42943–42947 (see updates for more information).

\begin{lemma}
\label{lemma-power-series-over-N-2}
Let $R$ be a ring.
If $R$ is Noetherian, a domain, and N-2, then so is $R[[x]]$.
\end{lemma}

\begin{proof}
Observe that $R[[x]]$ is Noetherian by
Lemma \ref{lemma-Noetherian-power-series}.
Let $R' \supset R$ be the integral closure of $R$ in its fraction
field. Because $R$ is N-2 this is finite over $R$. Hence $R'[[x]]$
is finite over $R[[x]]$. By
Lemma \ref{lemma-power-series-over-Noetherian-normal-domain}
we see that $R'[[x]]$ is a normal domain.
Apply Lemma \ref{lemma-tate-japanese} to the
element $x \in R'[[x]]$ to see that $R'[[x]]$ is N-2. Then
Lemma \ref{lemma-finite-extension-N-2} shows that $R[[x]]$ is N-2.
\end{proof}

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