Stacks project -- Comments

#9024 on tag 00S0 by Zheng Yang

Zheng Yang — Sat, 20 Apr 2024 06:02:19 GMT

There is a typo below Defn. 07BN in the description of the cotangent complex. The sentence should be corrected to read: "... the chain complex associated to the simplicial module..."

#9023 on tag 00NY by jack

jack — Sat, 20 Apr 2024 08:54:22 GMT

Here the formula defining R is recursive, but it should just be C^\inft(\mathbb{R}) of course. 052H has the same problem since it is a copy of this.

#9022 on tag 09DT by Zhenhua Wu

Zhenhua Wu — Fri, 19 Apr 2024 05:00:04 GMT

In the last line, the function $\sigma \circ (\sigma^\prime)^{-1}$ should be $\sigma^{-1}\circ \sigma^\prime$ .

#9021 on tag 010I by Stacks project

Stacks project — Fri, 19 Apr 2024 03:53:36 GMT

@#8412 Thanks and fixed here.

#9020 on tag 04GG by Stacks project

Stacks project — Fri, 19 Apr 2024 03:45:57 GMT

Thanks to the comments 8410, 8561, 8796, 8797. Fixed here.

#9019 on tag 00GH by Stacks project

Stacks project — Fri, 19 Apr 2024 03:30:57 GMT

Thanks and fixed here.

#9018 on tag 05TA by Stacks project

Stacks project — Fri, 19 Apr 2024 03:27:48 GMT

Thanks, this is indeed better. Fixed here.

#9017 on tag 0BND by Stacks project

Stacks project — Thu, 18 Apr 2024 02:56:49 GMT

Hahaha! Yes, of course. The notation is that $f_*$ is the map between groups and that the functor between the categories of sets with group actions is supposed to be induced by $f_*$ . See Lemma 58.3.11. Going to leave as is for now.

#9016 on tag 0EXL by Zhenhua Wu

Zhenhua Wu — Thu, 18 Apr 2024 03:41:24 GMT

The part ''It follows from Lemma 09HQ that $M′$ is normal over $K$ and that it is the smallest normal subextension of $\overline{K}$ containing $\sigma_i(L)$ needs clarification. To be specific: 1)why is $M'$ an field; 2)how do we use lemma 09HQ to show $M'/K$ is normal; 3) how do we show that it is the smallest normal subextension of $\overline{K}$ containing $\sigma_i(L)$ .

#9015 on tag 072V by James

James — Wed, 17 Apr 2024 05:22:45 GMT

Another mistake (mine of course): the dimension calculation above is 6-5. Apologies for the spam.