Definition 48.24.1. Let X be a scheme. We say X is Gorenstein if X is locally Noetherian and \mathcal{O}_{X, x} is Gorenstein for all x \in X.
48.24 Gorenstein schemes
This section is the continuation of Dualizing Complexes, Section 47.21.
This definition makes sense because a Noetherian ring is said to be Gorenstein if and only if all of its local rings are Gorenstein, see Dualizing Complexes, Definition 47.21.1.
Lemma 48.24.2. A Gorenstein scheme is Cohen-Macaulay.
Proof. Looking affine locally this follows from the corresponding result in algebra, namely Dualizing Complexes, Lemma 47.21.2. \square
Lemma 48.24.3. A regular scheme is Gorenstein.
Proof. Looking affine locally this follows from the corresponding result in algebra, namely Dualizing Complexes, Lemma 47.21.3. \square
Lemma 48.24.4. Let X be a locally Noetherian scheme.
If X has a dualizing complex \omega _ X^\bullet , then
X is Gorenstein \Leftrightarrow \omega _ X^\bullet is an invertible object of D(\mathcal{O}_ X),
\mathcal{O}_{X, x} is Gorenstein \Leftrightarrow \omega _{X, x}^\bullet is an invertible object of D(\mathcal{O}_{X, x}),
U = \{ x \in X \mid \mathcal{O}_{X, x}\text{ is Gorenstein}\} is an open Gorenstein subscheme.
If X is Gorenstein, then X has a dualizing complex if and only if \mathcal{O}_ X[0] is a dualizing complex.
Proof. Looking affine locally this follows from the corresponding result in algebra, namely Dualizing Complexes, Lemma 47.21.4. \square
Lemma 48.24.5. If f : Y \to X is a local complete intersection morphism with X a Gorenstein scheme, then Y is Gorenstein.
Proof. By More on Morphisms, Lemma 37.62.5 it suffices to prove the corresponding statement about ring maps. This is Dualizing Complexes, Lemma 47.21.7. \square
Lemma 48.24.6. The property \mathcal{P}(S) =“S is Gorenstein” is local in the syntomic topology.
Proof. Let \{ S_ i \to S\} be a syntomic covering. The scheme S is locally Noetherian if and only if each S_ i is Noetherian, see Descent, Lemma 35.16.1. Thus we may now assume S and S_ i are locally Noetherian. If S is Gorenstein, then each S_ i is Gorenstein by Lemma 48.24.5. Conversely, if each S_ i is Gorenstein, then for each point s \in S we can pick i and t \in S_ i mapping to s. Then \mathcal{O}_{S, s} \to \mathcal{O}_{S_ i, t} is a flat local ring homomorphism with \mathcal{O}_{S_ i, t} Gorenstein. Hence \mathcal{O}_{S, s} is Gorenstein by Dualizing Complexes, Lemma 47.21.8. \square
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