Processing math: 100%

The Stacks project

Lemma 5.21.6. Let f : X \to Y be a continuous map of topological spaces. Let T \subset Y be a subset. If f is open and T is a closed nowhere dense subset of Y, then also f^{-1}(T) is a closed nowhere dense subset of X. If f is surjective and open, then T is closed nowhere dense if and only if f^{-1}(T) is closed nowhere dense.

Proof. Omitted. (Hint: In the first case the interior of f^{-1}(T) maps into the interior of T, and in the second case the interior of f^{-1}(T) maps onto the interior of T.) \square


Comments (0)

There are also:

  • 2 comment(s) on Section 5.21: Nowhere dense sets

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.