Exercise 64.4.2 (03T1)—The Stacks project

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$\Lambda ^{\oplus m} \xrightarrow {a} \Lambda ^{\oplus n} \quad \text{and}\quad \Lambda ^{\oplus n} \xrightarrow {b} \Lambda ^{\oplus m}$

show that $\text{Tr}(ab) = \text{Tr}(ba)$ .

Comments (2)

Comment #6784 by 杜长江 on December 01, 2021 at 22:04

Maybe the source of $a$ should be $\Lambda^m$ ? Otherwise $ab$ is not well defined. (Moreover, to make sure the latter definition of trace is well defined, one needs $a$ to be a map from $\Lambda^m$ to $\Lambda^n$ )

Comment #6937 by Johan on January 20, 2022 at 18:56

Thanks and fixed here.

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