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The Stacks project

Example 64.14.5. Let C = E be an elliptic curve and \varphi = [n] be multiplication by n. Then \varphi ^* = \varphi ^ t is multiplication by n on the jacobian, so it has trace 2n and degree n^2. On the other hand, the fixed points of \varphi are the points p \in E such that n p = p, which is the (n-1)-torsion, which has cardinality (n-1)^2. So the theorem reads

(n-1)^2 = 1 - 2n + n^2.

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