Lemma 64.31.6. Algebraicity of eigenvalues. If \Lambda is a field then the eigenvalues t_ v for f\in C(\Lambda ) are algebraic over the prime subfield \mathbf{F} \subset \Lambda .
Proof. Follows from Proposition 64.31.5. \square
Lemma 64.31.6. Algebraicity of eigenvalues. If \Lambda is a field then the eigenvalues t_ v for f\in C(\Lambda ) are algebraic over the prime subfield \mathbf{F} \subset \Lambda .
Proof. Follows from Proposition 64.31.5. \square
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