Lemma 40.13.2. Let S be a scheme. Let (U, R, s, t, c) be a groupoid scheme over S. Let p \in S be a point, and let u \in U be a point lying over p. Assume assumptions (1) – (6) of Lemma 40.13.1 hold as well as
j : R \to U \times _ S U is universally closed1.
Then we can choose (S', p') \to (S, p) and decompositions S' \times _ S U = U' \amalg W and S' \times _ S R = R' \amalg W' and u' \in U' such that (a) – (g) of Lemma 40.13.1 hold as well as
R' is the restriction of S' \times _ S R to U'.
Proof.
We apply Lemma 40.13.1 for the groupoid (U, R, s, t, c) over the scheme S with points p and u. Hence we get an étale neighbourhood (S', p') \to (S, p) and disjoint union decompositions
S' \times _ S U = U' \amalg W, \quad S' \times _ S R = R' \amalg W'
and u' \in U' satisfying conclusions (a), (b), (c), (d), (e), (f), and (g). We may shrink S' to a smaller neighbourhood of p' without affecting the conclusions (a) – (g). We will show that for a suitable shrinking conclusion (h) holds as well. Let us denote j' the base change of j to S'. By conclusion (e) it is clear that
j'^{-1}(U' \times _{S'} U') = R' \amalg Rest
for some open and closed Rest piece. Since U' \to S' is finite by conclusion (d) we see that U' \times _{S'} U' is finite over S'. Since j is universally closed, also j' is universally closed, and hence j'|_{Rest} is universally closed too. By conclusions (b) and (c) we see that the fibre of
(U' \times _{S'} U' \to S') \circ j'|_{Rest} : Rest \longrightarrow S'
over p' is empty. Hence, since Rest \to S' is closed as a composition of closed morphisms, after replacing S' by S' \setminus \mathop{\mathrm{Im}}(Rest \to S'), we may assume that Rest = \emptyset . And this is exactly the condition that R' is the restriction of S' \times _ S R to the open subscheme U' \subset S' \times _ S U, see Groupoids, Lemma 39.18.3 and its proof.
\square
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