Lemma 5.9.3. Let f : X \to Y be a continuous map of topological spaces.
If X is Noetherian, then f(X) is Noetherian.
If X is locally Noetherian and f open, then f(X) is locally Noetherian.
Lemma 5.9.3. Let f : X \to Y be a continuous map of topological spaces.
If X is Noetherian, then f(X) is Noetherian.
If X is locally Noetherian and f open, then f(X) is locally Noetherian.
Proof. In case (1), suppose that Z_1 \supset Z_2 \supset Z_3 \supset \ldots is a descending chain of closed subsets of f(X) (as usual with the induced topology as a subset of Y). Then f^{-1}(Z_1) \supset f^{-1}(Z_2) \supset f^{-1}(Z_3) \supset \ldots is a descending chain of closed subsets of X. Hence this chain stabilizes. Since f(f^{-1}(Z_ i)) = Z_ i we conclude that Z_1 \supset Z_2 \supset Z_3 \supset \ldots stabilizes also. In case (2), let y \in f(X). Choose x \in X with f(x) = y. By assumption there exists a neighbourhood E \subset X of x which is Noetherian. Then f(E) \subset f(X) is a neighbourhood which is Noetherian by part (1). \square
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Comment #1362 by Pieter Belmans on
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