Lemma 60.8.3. In Situation 60.7.5. Let
be a fibre square in the category of divided power thickenings of X relative to (S, \mathcal{I}, \gamma ). If T_2 \to T is flat and U_2 = T_2 \times _ T U, then T_3 = T_1 \times _ T T_2 (as schemes).
Lemma 60.8.3. In Situation 60.7.5. Let
be a fibre square in the category of divided power thickenings of X relative to (S, \mathcal{I}, \gamma ). If T_2 \to T is flat and U_2 = T_2 \times _ T U, then T_3 = T_1 \times _ T T_2 (as schemes).
Proof. This is true because a divided power structure extends uniquely along a flat ring map. See Divided Power Algebra, Lemma 23.4.2. \square
Comments (2)
Comment #2313 by Daxin Xu on
Comment #2389 by Johan on
There are also: