For X irreducible we have \dim (X) = \dim (U) for any nonempty open U \subset X and \dim (X) = \dim _ x(X) for any x \in X.
Comments (0)
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
Comments (0)