Exercise 111.62.5 (Frobenius). Let p be a prime number (you may assume p = 2 to simplify the formulas). Let R be a ring such that p = 0 in R.
Show that the map F : R \to R, x \mapsto x^ p is a ring homomorphism.
Show that \mathop{\mathrm{Spec}}(F) : \mathop{\mathrm{Spec}}(R) \to \mathop{\mathrm{Spec}}(R) is the identity map.
Comments (0)