Lemma 6.4.2. Let X be a topological space. The category of presheaves of sets on X has products (see Categories, Definition 4.14.6). Moreover, the set of sections of the product \mathcal{F} \times \mathcal{G} over an open U is the product of the sets of sections of \mathcal{F} and \mathcal{G} over U.
Proof. Namely, suppose \mathcal{F} and \mathcal{G} are presheaves of sets on the topological space X. Consider the rule U \mapsto \mathcal{F}(U) \times \mathcal{G}(U), denoted \mathcal{F} \times \mathcal{G}. If V \subset U \subset X are open then define the restriction mapping
by mapping (s, t) \mapsto (s|_ V, t|_ V). Then it is immediately clear that \mathcal{F} \times \mathcal{G} is a presheaf. Also, there are projection maps p : \mathcal{F} \times \mathcal{G} \to \mathcal{F} and q : \mathcal{F} \times \mathcal{G} \to \mathcal{G}. We leave it to the reader to show that for any third presheaf \mathcal{H} we have \mathop{\mathrm{Mor}}\nolimits (\mathcal{H}, \mathcal{F} \times \mathcal{G}) = \mathop{\mathrm{Mor}}\nolimits (\mathcal{H}, \mathcal{F}) \times \mathop{\mathrm{Mor}}\nolimits (\mathcal{H}, \mathcal{G}). \square
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