Lemma 6.33.2. Let X be a topological space. Let X = \bigcup _{i\in I} U_ i be an open covering. Given any glueing data (\mathcal{F}_ i, \varphi _{ij}) for sheaves of sets with respect to the covering X = \bigcup U_ i there exists a sheaf of sets \mathcal{F} on X together with isomorphisms
\varphi _ i : \mathcal{F}|_{U_ i} \to \mathcal{F}_ i
such that the diagrams
\xymatrix{ \mathcal{F}|_{U_ i \cap U_ j} \ar[r]_{\varphi _ i} \ar[d]_{\text{id}} & \mathcal{F}_ i|_{U_ i \cap U_ j} \ar[d]^{\varphi _{ij}} \\ \mathcal{F}|_{U_ i \cap U_ j} \ar[r]^{\varphi _ j} & \mathcal{F}_ j|_{U_ i \cap U_ j} }
are commutative.
Proof.
First proof. In this proof we give a formula for the set of sections of \mathcal{F} over an open W \subset X. Namely, we define
\mathcal{F}(W) = \{ (s_ i)_{i \in I} \mid s_ i \in \mathcal{F}_ i(W \cap U_ i), \varphi _{ij}(s_ i|_{W \cap U_ i \cap U_ j}) = s_ j|_{W \cap U_ i \cap U_ j} \} .
Restriction mappings for W' \subset W are defined by the restricting each of the s_ i to W' \cap U_ i. The sheaf condition for \mathcal{F} follows immediately from the sheaf condition for each of the \mathcal{F}_ i.
We still have to prove that \mathcal{F}|_{U_ i} maps isomorphically to \mathcal{F}_ i. Let W \subset U_ i. In this case the condition in the definition of \mathcal{F}(W) implies that s_ j = \varphi _{ij}(s_ i|_{W \cap U_ j}). And the commutativity of the diagrams in the definition of a glueing data assures that we may start with any section s \in \mathcal{F}_ i(W) and obtain a compatible collection by setting s_ i = s and s_ j = \varphi _{ij}(s_ i|_{W \cap U_ j}).
Second proof (sketch). Let \mathcal{B} be the set of opens U \subset X such that U \subset U_ i for some i \in I. Then \mathcal{B} is a base for the topology on X. For U \in \mathcal{B} we pick i \in I with U \subset U_ i and we set \mathcal{F}(U) = \mathcal{F}_ i(U). Using the isomorphisms \varphi _{ij} we see that this prescription is “independent of the choice of i”. Using the restriction mappings of \mathcal{F}_ i we find that \mathcal{F} is a sheaf on \mathcal{B}. Finally, use Lemma 6.30.6 to extend \mathcal{F} to a unique sheaf \mathcal{F} on X.
\square
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