Lemma 10.38.4 (00H5)—The Stacks project

Processing math: 100%

Table of contents
Part 1: Preliminaries
Chapter 10: Commutative Algebra
Section 10.38: Going down for integral over normal
Lemma 10.38.4 (cite)

previous lemma
next lemma

numberstags

history
statistics
3 tags refer to this tag

Lemma 10.38.4. Suppose $\varphi : R \to S$ is integral. Suppose $I \subset R$ is an ideal. Then every element of $IS$ is integral over $I$ .

Proof. Immediate from Lemma 10.38.3. $\square$

Comments (0)

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$ ). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Comments (0)

Post a comment