Processing math: 100%

The Stacks project

Lemma 10.55.6. Let R = R_1 \times R_2. Then K_0(R) = K_0(R_1) \times K_0(R_2) and K'_0(R) = K'_0(R_1) \times K'_0(R_2)

Proof. Omitted. \square


Comments (0)

There are also:

  • 1 comment(s) on Section 10.55: K-groups

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.