The Stacks project

Lemma 10.75.2. Let $R$ be a ring and let $M$ be an $R$-module. Suppose that $0 \to N' \to N \to N'' \to 0$ is a short exact sequence of $R$-modules. There exists a long exact sequence

\[ \text{Tor}_1^ R(M, N') \to \text{Tor}_1^ R(M, N) \to \text{Tor}_1^ R(M, N'') \to M \otimes _ R N' \to M \otimes _ R N \to M \otimes _ R N'' \to 0 \]

Proof. The proof of this is the same as the proof of Lemma 10.71.6. $\square$

Comments (2)

Comment #3058 by Tanya Kaushal Srivastava on

The two lines of the long exact sequence for Tor should be switched.

There are also:

  • 2 comment(s) on Section 10.75: Tor groups and flatness

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 00M0. Beware of the difference between the letter 'O' and the digit '0'.



View Lemma 10.75.2 as pdf