Lemma 10.136.2. Let R \to S be a ring map. Let R \to R' be a faithfully flat ring map. Set S' = R'\otimes _ R S. Then R \to S is syntomic if and only if R' \to S' is syntomic.
Being syntomic is fpqc local on the base.
Proof. By Lemma 10.126.2 and Lemma 10.39.8 this holds for the property of being flat and for the property of being of finite presentation. The map \mathop{\mathrm{Spec}}(R') \to \mathop{\mathrm{Spec}}(R) is surjective, see Lemma 10.39.16. Thus it suffices to show given primes \mathfrak p' \subset R' lying over \mathfrak p \subset R that S \otimes _ R \kappa (\mathfrak p) is a local complete intersection if and only if S' \otimes _{R'} \kappa (\mathfrak p') is a local complete intersection. Note that S' \otimes _{R'} \kappa (\mathfrak p') = S \otimes _ R \kappa (\mathfrak p) \otimes _{\kappa (\mathfrak p)} \kappa (\mathfrak p'). Thus Lemma 10.135.11 applies. \square
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