Remark 7.15.3. There are many sites that give rise to the topos \mathop{\mathit{Sh}}\nolimits (pt). A useful example is the following. Suppose that S is a set (of sets) which contains at least one nonempty element. Let \mathcal{S} be the category whose objects are elements of S and whose morphisms are arbitrary set maps. Assume that \mathcal{S} has fibre products. For example this will be the case if S = \mathcal{P}(\text{infinite set}) is the power set of any infinite set (exercise in set theory). Make \mathcal{S} into a site by declaring surjective families of maps to be coverings (and choose a suitable sufficiently large set of covering families as in Sets, Section 3.11). We claim that \mathop{\mathit{Sh}}\nolimits (\mathcal{S}) is equivalent to the category of sets.
We first prove this in case S contains e \in S which is a singleton. In this case, there is an equivalence of topoi i : \mathop{\mathit{Sh}}\nolimits (pt) \to \mathop{\mathit{Sh}}\nolimits (\mathcal{S}) given by the functors
Namely, suppose that \mathcal{F} is a sheaf on \mathcal{S}. For any U \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{S}) = S we can find a covering \{ \varphi _ u : e \to U\} _{u \in U}, where \varphi _ u maps the unique element of e to u \in U. The sheaf condition implies in this case that \mathcal{F}(U) = \prod _{u \in U} \mathcal{F}(e). In other words \mathcal{F}(U) = \mathop{\mathrm{Mor}}\nolimits _{\textit{Sets}}(U, \mathcal{F}(e)). Moreover, this rule is compatible with restriction mappings. Hence the functor
is an equivalence of categories, and its inverse is the functor i^{-1} given above.
If \mathcal{S} does not contain a singleton, then the functor i_* as defined above still makes sense. To show that it is still an equivalence in this case, choose any nonempty \tilde e \in S and a map \varphi : \tilde e \to \tilde e whose image is a singleton. For any sheaf \mathcal{F} set
and show that this is a quasi-inverse to i_*. Details omitted.
Comments (0)
There are also: