Lemma 14.21.11. Let $\mathcal{C}$ be a category with finite coproducts and finite limits. Let $V$ be a simplicial object of $\mathcal{C}$. In this case
Proof. By Lemma 14.13.4 the object on the left represents the functor which assigns to $X$ the first set of the following equalities
The object on the right in the formula of the lemma is represented by the functor which assigns to $X$ the last set in the sequence of equalities. This proves the result.
In the sequence of equalities we have used that $\text{sk}_ n (X \times \Delta [n + 1]) = X \times \text{sk}_ n \Delta [n + 1]$ and that $i_{n!}(X \times \text{sk}_ n \Delta [n + 1]) = X \times i_{n !} \text{sk}_ n \Delta [n + 1]$. The first equality is obvious. For any (possibly truncated) simplicial object $W$ of $\mathcal{C}$ and any object $X$ of $\mathcal{C}$ denote temporarily $\mathop{\mathrm{Mor}}\nolimits _\mathcal {C}(X, W)$ the (possibly truncated) simplicial set $[n] \mapsto \mathop{\mathrm{Mor}}\nolimits _\mathcal {C}(X, W_ n)$. From the definitions it follows that $\mathop{\mathrm{Mor}}\nolimits (U \times X, W) = \mathop{\mathrm{Mor}}\nolimits (U, \mathop{\mathrm{Mor}}\nolimits _\mathcal {C}(X, W))$ for any (possibly truncated) simplicial set $U$. Hence
This proves the second equality used, and ends the proof of the lemma. $\square$
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)