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The Stacks project

Lemma 14.26.2. In the situation above, we have the following relations:

  1. We have h_{n, 0} = b_ n and h_{n, n + 1} = a_ n.

  2. We have d^ n_ j \circ h_{n, i} = h_{n - 1, i - 1} \circ d^ n_ j for i > j.

  3. We have d^ n_ j \circ h_{n, i} = h_{n - 1, i} \circ d^ n_ j for i \leq j.

  4. We have s^ n_ j \circ h_{n, i} = h_{n + 1, i + 1} \circ s^ n_ j for i > j.

  5. We have s^ n_ j \circ h_{n, i} = h_{n + 1, i} \circ s^ n_ j for i \leq j.

Conversely, given a system of maps h_{n, i} satisfying the properties listed above, then these define a morphism h which is a homotopy from a to b.

Proof. Omitted. You can prove the last statement using the fact, see Lemma 14.2.4 that to give a morphism of simplicial objects is the same as giving a sequence of morphisms h_ n commuting with all d^ n_ j and s^ n_ j. \square


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