Lemma 34.9.9. Let T be an affine scheme. Let \{ T_ i \to T\} _{i \in I} be an fpqc covering of T. Then there exists an fpqc covering \{ U_ j \to T\} _{j = 1, \ldots , n} which is a refinement of \{ T_ i \to T\} _{i \in I} such that each U_ j is an affine scheme. Moreover, we may choose each U_ j to be open affine in one of the T_ i.
Proof. This follows directly from the definition. \square
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