Lemma 34.9.8. Let $T$ be an affine scheme. Let $\{ T_ i \to T\} _{i \in I}$ be an fpqc covering of $T$. Then there exists an fpqc covering $\{ U_ j \to T\} _{j = 1, \ldots , n}$ which is a refinement of $\{ T_ i \to T\} _{i \in I}$ such that each $U_ j$ is an affine scheme. Moreover, we may choose each $U_ j$ to be open affine in one of the $T_ i$.

**Proof.**
This follows directly from the definition.
$\square$

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