Lemma 110.47.1. There exists an affine scheme X = \mathop{\mathrm{Spec}}(A) and an injective A-module J such that \widetilde{J} is not a flasque sheaf on X. Even the restriction \Gamma (X, \widetilde{J}) \to \Gamma (U, \widetilde{J}) with U a standard open need not be surjective.
110.47 Non flasque quasi-coherent sheaf associated to injective module
For more examples of this type see [Exposé II, Appendix I, SGA6] where Illusie explains some examples due to Verdier.
Consider the affine scheme X = \mathop{\mathrm{Spec}}(A) where
is the ring from Properties, Example 28.25.2. Set I = (x) \subset A. Consider the quasi-compact open U = D(x) of X. We have seen in loc. cit. that there is a section s \in \mathcal{O}_ X(U) which does not come from an A-module map I^ n \to A for any n \geq 0.
Let \alpha : A \to J be the embedding of A into an injective A-module. Let Q = J/\alpha (A) and denote \beta : J \to Q the quotient map. We claim that the map
is not surjective. Namely, we claim that \alpha (s) is not in the image. To see this, we argue by contradiction. So assume that x \in J is an element which restricts to \alpha (s) over U. Then \beta (x) \in Q is an element which restricts to 0 over U. Hence we know that I^ n\beta (x) = 0 for some n, see Properties, Lemma 28.25.1. This implies that we get a morphism \varphi : I^ n \to A, h \mapsto \alpha ^{-1}(hx). It is easy to see that this morphism \varphi gives rise to the section s via the map of Properties, Lemma 28.25.1 which is a contradiction.
Proof. See above. \square
In fact, we can use a similar construction to get an example of an injective module whose associated quasi-coherent sheaf has nonzero cohomology over a quasi-compact open. Namely, we start with the ring
where k is a field. Choose an injective map A \to I where I is an injective A-module. We claim that the element 1/xy in A_{xy} \subset I_{xy} is not in the image of I_ x \oplus I_ y \to I_{xy}. Arguing by contradiction, suppose that
for some n \geq 1 and i, j \in I. Clearing denominators we obtain
for some m \geq 0. Multiplying with u_{n + m}w_{n + m} we see that u_{n + m}w_{n + m}(xy)^{n + m - 1} = 0 in A which is the desired contradiction. Let U = D(x) \cup D(y) \subset X = \mathop{\mathrm{Spec}}(A). For any A-module M we have an exact sequence
by Mayer-Vietoris. We conclude that H^1(U, \widetilde{I}) is nonzero.
Lemma 110.47.2. There exists an affine scheme X = \mathop{\mathrm{Spec}}(A) whose underlying topological space is Noetherian and an injective A-module I such that \widetilde{I} has nonvanishing H^1 on some quasi-compact open U of X.
Proof. See above. Note that \mathop{\mathrm{Spec}}(A) = \mathop{\mathrm{Spec}}(k[x, y]) as topological spaces. \square
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