Processing math: 100%

The Stacks project

111.25 Fitting ideals

Exercise 111.25.1. Let R be a ring and let M be a finite R-module. Choose a presentation

\bigoplus \nolimits _{j \in J} R \longrightarrow R^{\oplus n} \longrightarrow M \longrightarrow 0.

of M. Note that the map R^{\oplus n} \to M is given by a sequence of elements x_1, \ldots , x_ n of M. The elements x_ i are generators of M. The map \bigoplus _{j \in J} R \to R^{\oplus n} is given by a n \times J matrix A with coefficients in R. In other words, A = (a_{ij})_{i = 1, \ldots , n, j \in J}. The columns (a_{1j}, \ldots , a_{nj}), j \in J of A are said to be the relations. Any vector (r_ i) \in R^{\oplus n} such that \sum r_ i x_ i = 0 is a linear combination of the columns of A. Of course any finite R-module has a lot of different presentations.

  1. Show that the ideal generated by the (n - k) \times (n - k) minors of A is independent of the choice of the presentation. This ideal is the kth Fitting ideal of M. Notation Fit_ k(M).

  2. Show that Fit_0(M) \subset Fit_1(M) \subset Fit_2(M) \subset \ldots . (Hint: Use that a determinant can be computed by expanding along a column.)

  3. Show that the following are equivalent:

    1. Fit_{r - 1}(M) = (0) and Fit_ r(M) = R, and

    2. M is locally free of rank r.


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.