
Lemma 10.157.4. Let $\varphi : R \to S$ be a ring map. Assume

1. $R$ is Noetherian,

2. $S$ is Noetherian,

3. $\varphi$ is flat,

4. the fibre rings $S \otimes _ R \kappa (\mathfrak p)$ are $(S_ k)$, and

5. $R$ has property $(S_ k)$.

Then $S$ has property $(S_ k)$.

Proof. Let $\mathfrak q$ be a prime of $S$ lying over a prime $\mathfrak p$ of $R$. By Lemma 10.157.2 we have

$\text{depth}(S_{\mathfrak q}) = \text{depth}(S_{\mathfrak q}/\mathfrak pS_{\mathfrak q}) + \text{depth}(R_{\mathfrak p}).$

On the other hand, we have

$\dim (R_{\mathfrak p}) + \dim (S_{\mathfrak q}/\mathfrak pS_{\mathfrak q}) \geq \dim (S_{\mathfrak q})$

by Lemma 10.111.6. (Actually equality holds, by Lemma 10.111.7 but strictly speaking we do not need this.) Finally, as the fibre rings of the map are assumed $(S_ k)$ we see that $\text{depth}(S_{\mathfrak q}/\mathfrak pS_{\mathfrak q}) \geq \min (k, \dim (S_{\mathfrak q}/\mathfrak pS_{\mathfrak q}))$. Thus the lemma follows by the following string of inequalities

\begin{eqnarray*} \text{depth}(S_{\mathfrak q}) & = & \text{depth}(S_{\mathfrak q}/\mathfrak pS_{\mathfrak q}) + \text{depth}(R_{\mathfrak p}) \\ & \geq & \min (k, \dim (S_{\mathfrak q}/\mathfrak pS_{\mathfrak q})) + \min (k, \dim (R_{\mathfrak p})) \\ & = & \min (2k, \dim (S_{\mathfrak q}/\mathfrak pS_{\mathfrak q}) + k, k + \dim (R_\mathfrak p), \dim (S_{\mathfrak q}/\mathfrak pS_{\mathfrak q}) + \dim (R_{\mathfrak p})) \\ & \geq & \min (k, \dim (S_{\mathfrak q})) \end{eqnarray*}

as desired. $\square$

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