Lemma 10.164.5. Let R \to S be a ring map. Assume that
R \to S is faithfully flat, and
S is Noetherian and has property (S_ k).
Then R is Noetherian and has property (S_ k).
Lemma 10.164.5. Let R \to S be a ring map. Assume that
R \to S is faithfully flat, and
S is Noetherian and has property (S_ k).
Then R is Noetherian and has property (S_ k).
Proof. We have already seen that (1) and (2) imply that R is Noetherian, see Lemma 10.164.1. Let \mathfrak p \subset R be a prime ideal. Choose a prime \mathfrak q \subset S lying over \mathfrak p which corresponds to a minimal prime of the fibre ring S \otimes _ R \kappa (\mathfrak p). Then A = R_{\mathfrak p} \to S_{\mathfrak q} = B is a flat local ring homomorphism of Noetherian local rings with \mathfrak m_ AB an ideal of definition of B. Hence \dim (A) = \dim (B) (Lemma 10.112.7) and \text{depth}(A) = \text{depth}(B) (Lemma 10.163.2). Hence since B has (S_ k) we see that A has (S_ k). \square
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