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changed the statement 2010-10-09 2b090dd
End conversion of etale to \'etale.
assigned tag 03WT 2010-01-03 92b033f
Tags: added new tags
created statement with label lemma-etale-open in morphisms.tex 2009-12-22 1c615f0
Morphisms of Spaces: Repaired lemma

	OK, so the lemma is fixed, and the proof is even kind of fun.
	The statement is that given a diagram

		V' ---> X' ---> X
			|	|
			v	v
			T' ---> T

	where T' --> T is an etale morphism of affine schemes, X an
	algebraic space, and X --> T is a separated locally quasi-finite
	morphism, and V' is an open subspace of X' which is a scheme and
	quasi-affine over T', then the image of V' in X is a scheme
	also. Of course this is subsumed in the final proposition that X
	in the situation above is actually a scheme!

	No matter: The question is whether one could prove a result like
	the above with a weakened hypothesis on the morphism X --> T.
	For example, suppose in the diagram above X --> T is only
	assumed quasi-separated, and we assume T' --> T is a finite
	etale Galois covering with group G. Then we can consider

		W' = \bigcap_{g \in G} g(V')

	This would still be quasi-affine over T', and its image in X a
	scheme, because W' comes with a natural descent datum for the
	morphism T' --> T.

	I assume that the condition of being Galois is too strong and it
	would suffice for T' --> T to just be finite locally free? But
	is there some part of this argument that survives if T' --> T is
	``just'' etale? Or is there some easy counter example?