History of tag 04T5
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type |
time |
link |
changed the proof
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2011-08-11 |
4c15ebf |
LaTeX: \Ob
Introduced a macro
\def\Ob{\mathop{\rm Ob}\nolimits}
and replaced any occurence of \text{Ob}( with \Ob(. There are
still some occurences of \text{Ob} but these are sets, not the
operator that takes the set of objects of a category.
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changed the statement
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2011-08-11 |
f496b59 |
LaTeX: \Sch
Introduced a new macro
\def\Sch{\textit{Sch}}
and replaced all the occurences of \textit{Sch} with \Sch.
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changed the label to lemma-stack-presentation
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2010-07-15 |
013229b |
Reduced algebraic stacks
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changed the statement
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2010-07-15 |
013229b |
Reduced algebraic stacks
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changed the statement and the proof
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2010-06-18 |
a283271 |
Definition of a presentation of an algebraic stack
Plus some small local improvements.
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assigned tag 04T5
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2010-06-17 |
72666b2
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Added new tags
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changed the proof
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2010-06-17 |
6246643 |
2-fibre products of algebraic stacks
This looks complicated because of or insistence that in the
first chapter on algebraic stacks we use a notation which
distinguishes between schemes, algebraic spaces, and algebraic
stacks.
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changed the statement and the proof
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2010-06-17 |
b866a0f |
More cleaning up of Algebraic Stacks
More or less OK proof of the easy direction for going between
algebraic stacks and presentations. It would be good to add more
material allowing us to work more easily with fibred
categories...
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created statement with label lemma-space-presentation in algebraic.tex
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2010-06-10 |
c70dda1 |
Every algebraic stack has a presentation
This is the easy direction, although there is plenty to improve
on here. We should split out some of the discussion in separate
lemmas. In particular, we should have a discussion on criteria
which garantee that a morphism of stacks in groupoids is an
equivalence. We should discuss more generally the construction
where given
U ---> X
with X an algebraic stack, U an algebraic space, on setting R =
U \times_X U we get a morphism of stacks in groupoids
[U/R] ---> X
for free. Then the lemma becomes much more readable and just
says that if U ---> X is smooth and surjective, then the
associated 1-morphism is an equivalence.
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