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The Stacks project

History of tag 04T5

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type time link
changed the proof 2011-08-11 4c15ebf
LaTeX: \Ob

	Introduced a macro

	\def\Ob{\mathop{\rm Ob}\nolimits}

	and replaced any occurence of \text{Ob}( with \Ob(. There are
	still some occurences of \text{Ob} but these are sets, not the
	operator that takes the set of objects of a category.
changed the statement 2011-08-11 f496b59
LaTeX: \Sch

	Introduced a new macro

	\def\Sch{\textit{Sch}}

	and replaced all the occurences of \textit{Sch} with \Sch.
changed the label to lemma-stack-presentation 2010-07-15 013229b
Reduced algebraic stacks
changed the statement 2010-07-15 013229b
Reduced algebraic stacks
changed the statement and the proof 2010-06-18 a283271
Definition of a presentation of an algebraic stack

	Plus some small local improvements.
assigned tag 04T5 2010-06-17 72666b2
Added new tags
changed the proof 2010-06-17 6246643
2-fibre products of algebraic stacks

	This looks complicated because of or insistence that in the
	first chapter on algebraic stacks we use a notation which
	distinguishes between schemes, algebraic spaces, and algebraic
	stacks.
changed the statement and the proof 2010-06-17 b866a0f
More cleaning up of Algebraic Stacks

	More or less OK proof of the easy direction for going between
	algebraic stacks and presentations. It would be good to add more
	material allowing us to work more easily with fibred
	categories...
created statement with label lemma-space-presentation in algebraic.tex 2010-06-10 c70dda1
Every algebraic stack has a presentation

	This is the easy direction, although there is plenty to improve
	on here. We should split out some of the discussion in separate
	lemmas. In particular, we should have a discussion on criteria
	which garantee that a morphism of stacks in groupoids is an
	equivalence. We should discuss more generally the construction
	where given
		U ---> X
	with X an algebraic stack, U an algebraic space, on setting R =
	U \times_X U we get a morphism of stacks in groupoids
		[U/R] ---> X
	for free. Then the lemma becomes much more readable and just
	says that if U ---> X is smooth and surjective, then the
	associated 1-morphism is an equivalence.