Proof.
First note that a finitely presented A-module is pure projective by Algebra, Theorem 10.82.3. Hence a direct summand of a direct sum of finitely presented A-modules is indeed pure projective. Let M be any A-module. Write M = \mathop{\mathrm{colim}}\nolimits _{i \in I} P_ i as a filtered colimit of finitely presented A-modules. Consider the sequence
0 \to N \to \bigoplus P_ i \to M \to 0.
For any finitely presented A-module P the map \mathop{\mathrm{Hom}}\nolimits _ A(P, \bigoplus P_ i) \to \mathop{\mathrm{Hom}}\nolimits _ A(P, M) is surjective, as any map P \to M factors through some P_ i. Hence by Algebra, Theorem 10.82.3 this sequence is universally exact. This proves (2). If now M is pure projective, then the sequence is split and we see that M is a direct summand of \bigoplus P_ i.
\square
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