Remark 105.4.2. We have the formula $S \times _{\mathcal{M}_{1, 1}} S' = (S \times S') \times _{\mathcal{M}_{1, 1} \times \mathcal{M}_{1, 1}} \mathcal{M}_{1, 1}$. Hence the key fact is a property of the diagonal $\Delta _{\mathcal{M}_{1, 1}}$ of $\mathcal{M}_{1, 1}$.

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