## 60.4 Compatibility

This section isn't required reading; it explains how our discussion fits with that of . Consider the following technical notion.

Definition 60.4.1. Let $(A, I, \gamma )$ and $(B, J, \delta )$ be divided power rings. Let $A \to B$ be a ring map. We say $\delta$ is compatible with $\gamma$ if there exists a divided power structure $\bar\gamma$ on $J + IB$ such that

$(A, I, \gamma ) \to (B, J + IB, \bar\gamma )\quad \text{and}\quad (B, J, \delta ) \to (B, J + IB, \bar\gamma )$

are homomorphisms of divided power rings.

Let $p$ be a prime number. Let $(A, I, \gamma )$ be a divided power ring. Let $A \to C$ be a ring map with $p$ nilpotent in $C$. Assume that $\gamma$ extends to $IC$ (see Divided Power Algebra, Lemma 23.4.2). In this situation, the (big affine) crystalline site of $\mathop{\mathrm{Spec}}(C)$ over $\mathop{\mathrm{Spec}}(A)$ as defined in is the opposite of the category of systems

$(B, J, \delta , A \to B, C \to B/J)$

where

1. $(B, J, \delta )$ is a divided power ring with $p$ nilpotent in $B$,

2. $\delta$ is compatible with $\gamma$, and

3. the diagram

$\xymatrix{ B \ar[r] & B/J \\ A \ar[u] \ar[r] & C \ar[u] }$

is commutative.

The conditions “$\gamma$ extends to $C$ and $\delta$ compatible with $\gamma$” are used in to insure that the crystalline cohomology of $\mathop{\mathrm{Spec}}(C)$ is the same as the crystalline cohomology of $\mathop{\mathrm{Spec}}(C/IC)$. We will avoid this issue by working exclusively with $C$ such that $IC = 0$1. In this case, for a system $(B, J, \delta , A \to B, C \to B/J)$ as above, the commutativity of the displayed diagram above implies $IB \subset J$ and compatibility is equivalent to the condition that $(A, I, \gamma ) \to (B, J, \delta )$ is a homomorphism of divided power rings.

 Of course there will be a price to pay.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).