Lemma 92.4.4. If A \to B is a ring map, then L\pi _!(\pi ^{-1}M) = M with \pi as in (92.4.0.1).
Proof. This follows from Lemma 92.4.1 which tells us L\pi _!(\pi ^{-1}M) is computed by (\pi ^{-1}M)(P_\bullet , \epsilon ) which is the constant simplicial object on M. \square
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