Lemma 92.27.1. In the situation above the category \mathcal{C}_{X/\Lambda } is fibred over X_{\acute{e}tale}.
Proof. Given an object U \to \mathbf{A} of \mathcal{C}_{X/\Lambda } and a morphism U' \to U of X_{\acute{e}tale} consider the object U' \to \mathbf{A} of \mathcal{C}_{X/\Lambda } where U' \to \mathbf{A} is the composition of U \to \mathbf{A} and U' \to U. The morphism (U' \to \mathbf{A}) \to (U \to \mathbf{A}) of \mathcal{C}_{X/\Lambda } is strongly cartesian over X_{\acute{e}tale}. \square
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