Lemma 5.23.3. Let f : X \to Y be a spectral map of spectral spaces. Then
f is continuous in the constructible topology,
the fibres of f are quasi-compact, and
the image is closed in the constructible topology.
Lemma 5.23.3. Let f : X \to Y be a spectral map of spectral spaces. Then
f is continuous in the constructible topology,
the fibres of f are quasi-compact, and
the image is closed in the constructible topology.
Proof. Let X' and Y' denote X and Y endowed with the constructible topology which are quasi-compact Hausdorff spaces by Lemma 5.23.2. Part (1) says X' \to Y' is continuous and follows immediately from the definitions. Part (3) follows as f(X') is a quasi-compact subset of the Hausdorff space Y', see Lemma 5.12.4. We have a commutative diagram
of continuous maps of topological spaces. Since Y' is Hausdorff we see that the fibres X'_ y are closed in X'. As X' is quasi-compact we see that X'_ y is quasi-compact (Lemma 5.12.3). As X'_ y \to X_ y is a surjective continuous map we conclude that X_ y is quasi-compact (Lemma 5.12.7). \square
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