Lemma 5.23.4. Let X and Y be spectral spaces. Let f : X \to Y be a continuous map. Then f is spectral if and only if f is continuous in the constructible topology.
Proof. The only if part of this is Lemma 5.23.3. Assume f is continuous in the constructible topology. Let V \subset Y be quasi-compact open. Then V is open and closed in the constructible topology. Hence f^{-1}(V) is open and closed in the constructible topology. Hence f^{-1}(V) is quasi-compact in the constructible topology as X is quasi-compact in the constructible topology by Lemma 5.23.2. Since the identity f^{-1}(V) \to f^{-1}(V) is surjective and continuous from the constructible topology to the usual topology, we conclude that f^{-1}(V) is quasi-compact in the topology of X by Lemma 5.12.7. This finishes the proof. \square
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