Lemma 47.15.12. Let A be a Noetherian ring. Let \omega _ A^\bullet be a dualizing complex. Let \mathfrak m \subset A be a maximal ideal and set \kappa = A/\mathfrak m. Then R\mathop{\mathrm{Hom}}\nolimits _ A(\kappa , \omega _ A^\bullet ) \cong \kappa [n] for some n \in \mathbf{Z}.
Proof. This is true because R\mathop{\mathrm{Hom}}\nolimits _ A(\kappa , \omega _ A^\bullet ) is a dualizing complex over \kappa (Lemma 47.15.9), because dualizing complexes over \kappa are unique up to shifts (Lemma 47.15.5), and because \kappa is a dualizing complex over \kappa . \square
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