Lemma 42.41.2. Let $k$ be a field. Let $X$ be proper over $k$. Let $\alpha = \sum n_ i[Z_ i]$ be in $Z_0(X)$. Then
\[ \deg (\alpha ) = \sum n_ i\deg (Z_ i) \]
where $\deg (Z_ i)$ is the degree of $Z_ i \to \mathop{\mathrm{Spec}}(k)$, i.e., $\deg (Z_ i) = \dim _ k \Gamma (Z_ i, \mathcal{O}_{Z_ i})$.
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