Lemma 53.6.5. In Situation 53.6.2. Given an exact sequence
\omega _ X \to \mathcal{F} \to \mathcal{Q} \to 0
of coherent \mathcal{O}_ X-modules with \dim (\text{Supp}(\mathcal{Q})) = 0 and \dim _ k H^0(X, \mathcal{Q}) \geq 2 and such that there is no nonzero submodule \mathcal{Q}' \subset \mathcal{F} such that \mathcal{Q}' \to \mathcal{Q} is injective. Then the submodule of \mathcal{F} generated by global sections surjects onto \mathcal{Q}.
Proof.
Let \mathcal{F}' \subset \mathcal{F} be the submodule generated by global sections and the image of \omega _ X \to \mathcal{F}. Since \dim _ k H^0(X, \mathcal{Q}) \geq 2 and \dim _ k H^1(X, \omega _ X) = \dim _ k H^0(X, \mathcal{O}_ X) = 1, we see that \mathcal{F}' \to \mathcal{Q} is not zero and \omega _ X \to \mathcal{F}' is not an isomorphism. Hence H^1(X, \mathcal{F}') = 0 by Lemma 53.6.3 and our assumption on \mathcal{F}. Consider the short exact sequence
0 \to \mathcal{F}' \to \mathcal{F} \to \mathcal{Q}/\mathop{\mathrm{Im}}(\mathcal{F}' \to \mathcal{Q}) \to 0
If the quotient on the right is nonzero, then we obtain a contradiction because then H^0(X, \mathcal{F}) is bigger than H^0(X, \mathcal{F}').
\square
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