Lemma 15.60.2. Let $R \to A$ be a ring map. Let $f : L^\bullet \to N^\bullet $ be a map of complexes of $A$-modules. Then $f$ induces a transformation of functors
If $f$ is a quasi-isomorphism, then $1 \otimes f$ is an isomorphism of functors.
Lemma 15.60.2. Let $R \to A$ be a ring map. Let $f : L^\bullet \to N^\bullet $ be a map of complexes of $A$-modules. Then $f$ induces a transformation of functors
If $f$ is a quasi-isomorphism, then $1 \otimes f$ is an isomorphism of functors.
Proof. Since the functors are computing by evaluating on K-flat complexes $K^\bullet $ we can simply use the functoriality
to define the transformation. The last statement follows from Lemma 15.59.2. $\square$
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)