Remark 53.19.9 (Trivial quadratic extension). Let $k$ be a field. Let $(A, \mathfrak m, \kappa )$ be as in Remark 53.19.8 and let $\kappa '/\kappa $ be the associated separable algebra of degree $2$. Then the following are equivalent

$\kappa ' \cong \kappa \times \kappa $ as $\kappa $-algebra,

the form $q$ of Lemma 53.19.3 can be chosen to be $xy$,

$A$ has two branches,

the extension $A'/A$ of Lemma 53.19.4 has two maximal ideals, and

$A^\wedge \cong \kappa [[x, y]]/(xy)$ as a $k$-algebra.

The equivalence between these conditions has been shown in the proof of Lemma 53.19.4. If $X$ is a locally Noetherian $k$-scheme and $x \in X$ is a point such that $\mathcal{O}_{X, x} = A$, then this means exactly that there are two points $x_1, x_2$ of the normalization $X^\nu $ lying over $x$ and that $\kappa (x) = \kappa (x_1) = \kappa (x_2)$.

## Comments (0)