The Stacks project

Lemma 99.8.3. In Situation 99.8.1. Let $T$ be an algebraic space over $S$. We have

\[ \mathop{\mathrm{Mor}}\nolimits _{\mathop{\mathit{Sh}}\nolimits ((\mathit{Sch}/S)_{fppf})}(T, \mathrm{Quot}_{\mathcal{F}/X/B}) = \left\{ \begin{matrix} (h, \mathcal{F}_ T \to \mathcal{Q}) \text{ where } h : T \to B \text{ and} \\ \mathcal{Q}\text{ is of finite presentation and} \\ \text{flat over }T\text{ with support proper over }T \end{matrix} \right\} \]

where $\mathcal{F}_ T$ denotes the pullback of $\mathcal{F}$ to the algebraic space $X \times _{B, h} T$.

Proof. Observe that the left and right hand side of the equality are subsets of the left and right hand side of the second equality in Lemma 99.7.5. To see that these subsets correspond under the identification given in the proof of that lemma it suffices to show: given $h : T \to B$, a surjective étale morphism $U \to T$, a finite type quasi-coherent $\mathcal{O}_{X_ T}$-module $\mathcal{Q}$ the following are equivalent

  1. the scheme theoretic support of $\mathcal{Q}$ is proper over $T$, and

  2. the scheme theoretic support of $(X_ U \to X_ T)^*\mathcal{Q}$ is proper over $U$.

This follows from Descent on Spaces, Lemma 74.11.19 combined with Morphisms of Spaces, Lemma 67.30.10 which shows that taking scheme theoretic support commutes with flat base change. $\square$


Comments (0)


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0D3V. Beware of the difference between the letter 'O' and the digit '0'.