Lemma 69.4.4. With S, X, Y, \pi , \mathcal{A}, \mathcal{B}, \varphi , and f as in Lemma 69.4.3 we have
in D(\mathcal{B}) for any K \in D(\mathcal{B}) and M \in D(\mathcal{A}).
Lemma 69.4.4. With S, X, Y, \pi , \mathcal{A}, \mathcal{B}, \varphi , and f as in Lemma 69.4.3 we have
in D(\mathcal{B}) for any K \in D(\mathcal{B}) and M \in D(\mathcal{A}).
Proof. Since f_* is exact (Lemma 69.4.1) the functor Rf_* is computed by applying f_* to any representative complex. Choose a complex \mathcal{K}^\bullet of \mathcal{B}-modules representing K which is K-flat with flat terms, see Cohomology on Sites, Lemma 21.17.11. Then f^*\mathcal{K}^\bullet is K-flat with flat terms, see Cohomology on Sites, Lemma 21.18.1. Choose any complex \mathcal{M}^\bullet of \mathcal{A}-modules representing M. Then we have to show
because by our choices these complexes represent the right and left hand side of the formula in the lemma. Since f_* commutes with direct sums (for example by the description of the stalks in Lemma 69.4.2), this reduces to the equalities
which are true by Lemma 69.4.3. \square
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