Processing math: 100%

The Stacks project

Lemma 93.7.2. Example 93.7.1 satisfies the Rim-Schlessinger condition (RS). In particular, \mathcal{D}\! \mathit{ef}_ P is a deformation category for any graded k-algebra P.

Proof. Let A_1 \to A and A_2 \to A be morphisms of \mathcal{C}_\Lambda . Assume A_2 \to A is surjective. According to Formal Deformation Theory, Lemma 90.16.4 it suffices to show that the functor \mathcal{F}(A_1 \times _ A A_2) \to \mathcal{F}(A_1) \times _{\mathcal{F}(A)} \mathcal{F}(A_2) is an equivalence of categories.

Consider an object

((A_1, P_1), (A_2, P_2), (\text{id}_ A, \varphi ))

of the category \mathcal{F}(A_1) \times _{\mathcal{F}(A)} \mathcal{F}(A_2). Then we consider P_1 \times _\varphi P_2. Since \varphi : P_1 \otimes _{A_1} A \to P_2 \otimes _{A_2} A is an isomorphism of graded algebras, we see that the graded pieces of P_1 \times _\varphi P_2 are finite projective A_1 \times _ A A_2-modules, see proof of Lemma 93.4.2. Thus P_1 \times _\varphi P_2 is an object of \mathcal{F}(A_1 \times _ A A_2). This construction determines a quasi-inverse to our functor and the proof is complete. \square


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.