The Stacks project

Lemma 53.14.1. In the situation above, let $Z = \mathop{\mathrm{Spec}}(k')$ where $k'$ is a field and $Z' = \mathop{\mathrm{Spec}}(k'_1 \times \ldots \times k'_ n)$ with $k'_ i/k'$ finite extensions of fields. Let $x \in X$ be the image of $Z \to X$ and $x'_ i \in X'$ the image of $\mathop{\mathrm{Spec}}(k'_ i) \to X'$. Then we have a fibre product diagram

\[ \xymatrix{ \prod \nolimits _{i = 1, \ldots , n} k'_ i & \prod \nolimits _{i = 1, \ldots , n} \mathcal{O}_{X', x'_ i}^\wedge \ar[l] \\ k' \ar[u] & \mathcal{O}_{X, x}^\wedge \ar[u] \ar[l] } \]

where the horizontal arrows are given by the maps to the residue fields.

Proof. Choose an affine open neighbourhood $\mathop{\mathrm{Spec}}(A)$ of $x$ in $X$. Let $\mathop{\mathrm{Spec}}(A') \subset X'$ be the inverse image. By construction we have a fibre product diagram

\[ \xymatrix{ \prod \nolimits _{i = 1, \ldots , n} k'_ i & A' \ar[l] \\ k' \ar[u] & A \ar[u] \ar[l] } \]

Since everything is finite over $A$ we see that the diagram remains a fibre product diagram after completion with respect to the maximal ideal $\mathfrak m \subset A$ corresponding to $x$ (Algebra, Lemma 10.97.2). Finally, apply Algebra, Lemma 10.97.8 to identify the completion of $A'$. $\square$


Comments (0)


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0E36. Beware of the difference between the letter 'O' and the digit '0'.