Lemma 42.6.3 (Key Lemma). Let A be a 2-dimensional Noetherian local domain with fraction field K. Let f, g \in K^*. Let \mathfrak q_1, \ldots , \mathfrak q_ t be the height 1 primes \mathfrak q of A such that either f or g is not an element of A^*_{\mathfrak q}. Then we have
\sum \nolimits _{i = 1, \ldots , t} \text{ord}_{A/\mathfrak q_ i}(\partial _{A_{\mathfrak q_ i}}(f, g)) = 0
We can also write this as
\sum \nolimits _{\text{height}(\mathfrak q) = 1} \text{ord}_{A/\mathfrak q}(\partial _{A_{\mathfrak q}}(f, g)) = 0
since at any height 1 prime \mathfrak q of A where f, g \in A^*_{\mathfrak q} we have \partial _{A_{\mathfrak q}}(f, g) = 1.
Proof.
Since the tame symbols \partial _{A_{\mathfrak q}}(f, g) are bilinear and the order functions \text{ord}_{A/\mathfrak q} are additive it suffices to prove the formula when f and g are elements of A. This case is proven in Lemma 42.6.2.
\square
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