Remark 42.37.10. Let $(S, \delta )$ be as in Situation 42.7.1. Let $X$ be locally of finite type over $S$. Let $\mathcal{E}$ be a finite locally free $\mathcal{O}_ X$-module. If the rank of $\mathcal{E}$ is not constant then we can still define the Chern classes of $\mathcal{E}$. Namely, in this case we can write

$X = X_0 \amalg X_1 \amalg X_2 \amalg \ldots$

where $X_ r \subset X$ is the open and closed subspace where the rank of $\mathcal{E}$ is $r$. By Lemma 42.34.4 we have $A^ p(X) = \prod A^ p(X_ r)$. Hence we can define $c_ i(\mathcal{E})$ to be the product of the classes $c_ i(\mathcal{E}|_{X_ r})$ in $A^ i(X_ r)$. Explicitly, if $X' \to X$ is a morphism locally of finite type, then we obtain by pullback a corresponding decomposition of $X'$ and we find that

$\mathop{\mathrm{CH}}\nolimits _*(X') = \prod \nolimits _{r \geq 0} \mathop{\mathrm{CH}}\nolimits _*(X'_ r)$

by our definitions. Then $c_ i(\mathcal{E}) \in A^ i(X)$ is the bivariant class which preserves these direct product decompositions and acts by the already defined operations $c_ i(\mathcal{E}|_{X_ r}) \cap -$ on the factors. Observe that in this setting it may happen that $c_ i(\mathcal{E})$ is nonzero for infinitely many $i$. In this setting we moreover define the “rank” of $\mathcal{E}$ to be the element $r(\mathcal{E}) \in A^0(X)$ as the bivariant operation which sends $(\alpha _ r) \in \prod \mathop{\mathrm{CH}}\nolimits _*(X'_ r)$ to $(r\alpha _ r) \in \prod \mathop{\mathrm{CH}}\nolimits _*(X'_ r)$. Note that it is still true that $c_ i(\mathcal{E})$ and $r(\mathcal{E})$ are in the center of $A^*(X)$.

There are also:

• 2 comment(s) on Section 42.37: Intersecting with Chern classes

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).