Lemma 35.13.4. Let \{ f_ i : X_ i \to X\} _{i \in I} be a family of morphisms of schemes. If for every morphism Y \to X with Y affine the family of base changes g_ i : Y_ i \to Y forms an effective epimorphism, then the family of f_ i forms a universal effective epimorphism in the category of schemes.
Proof. Let Y \to X be a morphism of schemes. We have to show that the base changes g_ i : Y_ i \to Y form an effective epimorphism. To do this, assume given a scheme T and morphisms h_ i : Y_ i \to T with h_ i \circ \text{pr}_1 = h_ j \circ \text{pr}_2 on Y_ i \times _ Y Y_ j. Choose an affine open covering Y = \bigcup V_\alpha . Set V_{\alpha , i} equal to the inverse image of V_\alpha in Y_ i. Then we see that V_{\alpha , i} \to V_\alpha is the base change of f_ i by V_\alpha \to X. Thus by assumption the family of restrictions h_ i|_{V_{\alpha , i}} come from a morphism of schemes h_\alpha : V_\alpha \to T. We leave it to the reader to show that these agree on overlaps and define the desired morphism Y \to T. See discussion in Schemes, Section 26.14. \square
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